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#脑洞时间 - 推理桌游《献忠杀》
1.受推友@YuzurihaIG启发,做个游戏策划:结合狼人杀和三国杀的玩法,13玩家+1裁判通过随机抽身份牌组成四个阵营:
-TG(老大哥,赵家人,粉红x2):保护TG阵营
-反贼x4:消灭老大哥
-献忠:消灭除自己的所有人
-中立(老外,润学家,打假师,医生):确保自己最终存活 Image
2. 游戏流程:

类似狼人杀,晚上闭眼,白天睁眼
献忠每晚必须任选一人杀之

白天所有存活玩家进行推理讨论,但不进行投票
第一个白天老大哥和老外公开身份,以后每个白天老大哥自行决定枪毙一人
被杀玩家身份游戏结束后才会揭晓

获胜阵营的存活成员+3分。任何玩家只要存活就+1分。阵亡玩家不加分
3胜负判定:

TG胜:反贼和献忠全灭(但老大哥和赵家人最后只能活一个,若此时两人都存活赵家人会立即死亡)

反贼胜:老大哥,赵家人,献忠均被杀(不需要杀粉红)

献忠胜:杀光所有玩家。最后只剩自己和无能力杀人者也算献忠胜

中立阵营胜:最后只剩中立阵营;或只剩献忠和中立阵营,但润学家成功脱出
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