If in a staggered DiD setting I write an equation with a full set of treatment indicators by treated cohort and calendar time, and include c(i) + f(t) (unit and time "fixed effects"), would you still call that a "fixed effects" model?
If you answer "yes" then you should stop saying things like "there's a problem with the TWFE 'model'." The modeling is our choice; we choose what to put in x(i,t) when we write

y(i,t) = x(i,t)*b + c(i) + f(t) + u(i,t)

The phrase "TWFE model" refers to c(i) + f(t), right?
If x(i,t) = w(i,t) -- a single treatment indicator -- then the model might be too restrictive. But as I've shown in my DiD work, it's easy to put more in x(i,t) and estimate a full set of heterogeneous TEs. But I can (and should) still use the TWFE estimator.
Which gets back to my point that I'm not a fan of the phrase "TWFE model," as if there is some immutable model that we have no control over. The problem is our modeling, not the TWFE estimator. Do I blame the maximum likelihood estimator when I apply it to a poor model?
So if you see that someone has estimated the constant effect model by TWFE, emphasize they should also try making the model more flexible and then estimate the extended model by TWFE. This turns out to be the same as a pooled OLS, RE, and imputation method.
Just want to make sure we're all on the same page with the recent DiD literature. It should be uncontroversial to distinguish between the model and the estimation method. We can get pretty far with traditional estimation methods.

#metricstotheface

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More from @jmwooldridge

Feb 18
Not exactly. I like Bruce's approach in this paper and it yields nice insights. But in twitter and private exchanges last week, and what I've learned since, it seems that the class of estimators in play in Theorem 5 include only estimators that are linear in Y.

#metricstotheface
Theorem 5 is correct and neat, but leaves open the question of which estimators are in the class that is being compared with OLS. Remember, we cannot simply use phrases such as "OLS is BUE" without clearly defining the competing class of estimators. This is critical.
The class of distributions in F2 is so large -- only restricting the mean to be linear in X and assuming finite second moments -- that it's not surprising the class of unbiased estimators is "small." So small, it is estimators linear in Y.
Read 11 tweets
Feb 13
Concerning the recent exchange many of us had about @BruceEHansen's new Gauss-Markov Theorem, I now understand a lot more and can correct/clarify several things I wrote yesterday. I had a helpful email exchange with Bruce that confirmed my thinking.

#metricstotheface
A lot was written about the "linear plus quadratic" class of estimators as possible competitors to OLS. Here's something important to know: Bruce's result does not allow these estimators in the comparison group with OLS unless they are actually linear; no quadratic terms allowed.
If one looks at Theorem 5 concerning OLS, you'll see a distinction between F2 and F2^0. All estimators in the comparison group must be unbiased under the very large class of distributions, F2. This includes all distributions with finite second moments -- so unrestricted SIGMA.
Read 13 tweets
Feb 13
This is neat and makes sense to me. After all, third moments need not even exist under GM. And using 3rd moments would make it very tough to achieve unbiasedness across all cases with only GM. Clearly, the result says it's impossible
It still blows my mind that that OLS is best unbiased in that class. Across all multivariate distributions with weird 3rd and 4th conditional moments, and beyond. As I said in a previous tweet, this would not be true in an asymptotic setting.
The Koopmann result prompts a question that I've wondered about off and on. If you use the first 3 GM assumptions, which I write as
A1. Y = X*b + U
A2. rank(X) = k
A3. E(U|X) = 0
then, for A n x k, a linear estimator A'Y is unbiased if and only if A'X = I (n x n).
Read 4 tweets
Feb 12
One of the remarkable features of Bruce's result, and why I never could have discovered it, is that the "asymptotic" analog doesn't seem to hold. Suppose we assume random sampling and in the population specify

A1. E(y|x) = x*b0
A2. Var(y|x) = (s0)^2

#metricstotheface
Also assume rank E(x'x) = k so no perfect collinearity in the population. Then OLS is asymptotically efficient among estimators that only use A1 for consistency. But OLS is not asymp effic among estimators that use A1 and A2 for consistency.
A2 adds many extra moment conditions that, generally, are useful for estimating b0 -- for example, if D(y|x) is asymmetric with third central moment depending on x. So there are GMM estimators more asymp efficient than OLS under A1 and A2.
Read 5 tweets
Jan 18
Here's an example I use in the summer ESTIMATE course at MSU. It's based on an actual contingent valuation survey. There are two prices, one of regular apples the other of "ecologically friendly" apples. The prices were randomly assigned as a pair, (PR, PE).

#metricstotheface
Individuals were then asked to choose a basket of regular and eco-friendly applies. A linear regression for QE (quantity of eco-labeled) gives very good results: strong downward sloping demand curve, an increase in the competing price shifts out the demand curve.
Now, the prices were generated to be highly correlated with, corr = 0.83. Not VIF > 10 territory but a pretty high correlation. If PR is dropped from the equation for QE, the estimated price effect for PE falls dramatically -- because there's an important omitted variable, PR.
Read 5 tweets
Jan 18
If you know people who teach students it's important to "test" for multicollinearity, please ask them why.

I imagine a world where the phrase "I tested for multicollinearity" no longer appears in published work. I know John Lennon would be on my side.

#metricstotheface
What I'm getting at is that it's still common to see "tests" for multicollinearity without even looking at the regression output. Or asking which variables are collinear. Often it's control variables. So what? If you have many control variables you might have to select.
And a VIF of 9.99 is okay but 10.01 is a disaster? We can do better than this across all fields.

I just saw a post where X1 and X2 have a correlation of .7, and the researcher wonders which variable to drop.
Read 6 tweets

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