Thread by @Hajun_BY

Today the Russian MiG-31K was flying without the A-50U.
The MiG-31K took off from Machulishchy airfield at 09:00 and landed at 11:01 (Kyiv time). An escort fighter took off from Baranavichy airfield together with it.
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However, due to the absence of the A-50U AEW&C aircraft in the sky over Belarus, the probability of launch of Kinzhal hypersonic missiles from the MiG-31K of the Russian Aerospace Forces slightly decreased.
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The main purpose of the A-50U in the Belarusian airspace was to “scan” northern Ukraine, among other things, to detect air defense and aviation activities in the air.
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In particular, to ensure that the MiG-31K could safely for itself and “at the right time” launch a missile to bypass Ukraine’s air defense if needed, in other words, so that both the MiG and the missile would not be shot down.
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The Russian A-50U aircraft (RF-50608), which could have been damaged in the Machulishchy incident on February 26, took off from Machulishchy airfield at 11:24 (Kyiv time) yesterday and, according to our information, flew to the 325th Aircraft Repair Plant in Taganrog.
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According to our data, when leaving Belarus, the A-50U flew at a low altitude of up to 4 km. The reason is that an altitude of 3 - 4 thousand meters is considered safe for the crew in case of loss of pressurisation.
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And this is despite the fact that the aircraft is equipped with an emergency oxygen supply system.
Also, yesterday the Russian An-26 left Belarus together with the A-50U and flew to Taganrog.
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This is an additional evidence of the fact that on February 26 a repair team from Ivanovo arrived in Belarus, and on February 28 a repair team from Taganrog arrived there, together they were repairing the aircraft for 4 days and then flew to Taganrog with the A-50U.
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According to the version of propaganda, “the plane flew over the state border of the Republic of Belarus.” As we see, the “flight” has already lasted for 25 hours, given that the maximum duration of the flight of this aircraft without refueling is 9,3 hours.
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