Tivadar Danka Profile picture
Jun 26, 2025 18 tweets 5 min read Read on X
Problem-solving is at least 50% of every job in tech and science.

Mastering problem-solving will make your technical skill level shoot up like a hockey stick. Yet, we are rarely taught how to do so.

Here are my favorite techniques that'll loosen even the most complex knots: Image
0. Is the problem solved yet?

The simplest way to solve a problem is to look for the solution elsewhere. This is not cheating; this is pragmatism. (Except if it is a practice problem. Then, it is cheating.)
When your objective is to move fast, this should be the first thing you attempt.

This is the reason why Stack Overflow (and its likes) are the best friends of every programmer.
1. Is there an analogous problem?

If A is analogous to B, and A plays a role in your problem, swapping them might reveal an insight into your problem.

An example: circles and spheres are analogous, as they are the same objects in different dimensions. Image
Thus, if you are facing a geometric problem that involves spheres, bumping it down a dimension can highlight a simpler solution that can be mapped to the source problem.
Quoting Stefan Banach (the inventor of functional analysis), "A mathematician is a person who can find analogies between theorems; a better mathematician is one who can see analogies between proofs and the best mathematician can notice analogies between theories."
2. Wishful thinking.

Sometimes, the best thing to do is pretend the solution exists and move forward.

I’ll illustrate this with a mathematical example. Let’s talk about the Singular Value Decomposition (SVD).
This famous result states that every real matrix A can be decomposed into a product of an

1. orthogonal matrix U (that is, UUᵀ is the identity matrix),
2. a diagonal matrix Σ,
3. and another orthogonal matrix Vᵀ.

We find them via wishful thinking: we pretend that they exist. Image
If they do, then AAᵀ, which is a real symmetric matrix, equals to AAᵀ = UΣ²Uᵀ. This U can be found via the spectral decomposition theorem! We can find V similarly.

We found U and V by pretending they exist. Image
3. Can you solve a special case?

Reducing the problem to a special case is also an extremely powerful technique. The previously shown SVD was solved by reducing the general case to the real symmetric case. Image
4. Is this a special case of a general problem?

This is the counterpart of the previous case and can be similarly powerful.

For instance, consider this geometric shape. Is there a vertical cut that cuts this into two parts of equal area? Image
Our first instinct is to start calculating its area up to a cutoff, but this is extremely complicated.

All we have to notice is that the area given the position of the vertical slice is a continuous function. Image
As f(0) = 0, f(1) = area, and f is continuous, it has to cross area/2.

This is a general result, and our problem is a special case of this. It doesn’t matter what f is exactly.

Much simpler than solving equations involving inverse trigonometric functions. Image
(By the way, here is the vertical cut that splits the object into equal-sized parts.) Image
5. Can you draw a picture?

Our thinking is more visual than formal, and solving problems is much easier visually too.

The simplest example is probably the De Morgan identities: they are trivial to see visually, but more difficult to prove formally. Image
6. Is there a simpler approach?

Our first ideas are often vastly overcomplicated, taking us down a rabbit hole we don't need to go.

For example, I have posted a simple puzzle a few years ago about poles and cables. Here it is: Image
The first idea is to use catenary curves and calculus, but there is a simple solution: as the cables hang 10 m above ground, they drop 40 m from the top of the pole. Hence, the distance between the two poles must be 0 m.

Simplifying our approach is always beneficial.
If you liked this thread, you will love The Palindrome, my weekly newsletter on Mathematics and Machine Learning.

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More from @TivadarDanka

Jan 20
The single most undervalued fact of linear algebra: matrices are graphs, and graphs are matrices.

Encoding matrices as graphs is a cheat code, making complex behavior simple to study.

Let me show you how! Image
If you looked at the example above, you probably figured out the rule.

Each row is a node, and each element represents a directed and weighted edge. Edges of zero elements are omitted.

The element in the 𝑖-th row and 𝑗-th column corresponds to an edge going from 𝑖 to 𝑗.
To unwrap the definition a bit, let's check the first row, which corresponds to the edges outgoing from the first node. Image
Read 18 tweets
Jan 14
Matrix multiplication is not easy to understand.

Even looking at the definition used to make me sweat, let alone trying to comprehend the pattern. Yet, there is a stunningly simple explanation behind it.

Let's pull back the curtain! Image
First, the raw definition.

This is how the product of A and B is given. Not the easiest (or most pleasant) to look at.

We are going to unwrap this. Image
Here is a quick visualization before the technical details.

The element in the i-th row and j-th column of AB is the dot product of A's i-th row and B's j-th column. Image
Read 17 tweets
Jan 8
Behold one of the mightiest tools in mathematics: the camel principle.

I am dead serious. Deep down, this tiny rule is the cog in many methods. Ones that you use every day.

Here is what it is, how it works, and why it is essential: Image
First, the story:

The old Arab passes away, leaving half of his fortune to his eldest son, third to his middle son, and ninth to his smallest.

Upon opening the stable, they realize that the old man had 17 camels. Image
This is a problem, as they cannot split 17 camels into 1/2, 1/3, and 1/9 without cutting some in half.

So, they turn to the wise neighbor for advice. Image
Read 18 tweets
Jan 1
The single most undervalued fact of linear algebra: matrices are graphs, and graphs are matrices.

Encoding matrices as graphs is a cheat code, making complex behavior simple to study.

Let me show you how! Image
If you looked at the example above, you probably figured out the rule.

Each row is a node, and each element represents a directed and weighted edge. Edges of zero elements are omitted.

The element in the 𝑖-th row and 𝑗-th column corresponds to an edge going from 𝑖 to 𝑗.
To unwrap the definition a bit, let's check the first row, which corresponds to the edges outgoing from the first node. Image
Read 18 tweets
Dec 11, 2025
The single most undervalued fact of linear algebra: matrices are graphs, and graphs are matrices.

Encoding matrices as graphs is a cheat code, making complex behavior simple to study.

Let me show you how! Image
If you looked at the example above, you probably figured out the rule.

Each row is a node, and each element represents a directed and weighted edge. Edges of zero elements are omitted.

The element in the 𝑖-th row and 𝑗-th column corresponds to an edge going from 𝑖 to 𝑗.
To unwrap the definition a bit, let's check the first row, which corresponds to the edges outgoing from the first node. Image
Read 18 tweets
Dec 9, 2025
Matrix multiplication is not easy to understand.

Even looking at the definition used to make me sweat, let alone trying to comprehend the pattern. Yet, there is a stunningly simple explanation behind it.

Let's pull back the curtain! Image
First, the raw definition.

This is how the product of A and B is given. Not the easiest (or most pleasant) to look at.

We are going to unwrap this. Image
Here is a quick visualization before the technical details.

The element in the i-th row and j-th column of AB is the dot product of A's i-th row and B's j-th column. Image
Read 17 tweets

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