If my school building was running the way it was supposed to be run (compliant to minimum codes), how would it rate per Harvard-CU Boulder Air Exchange Rate Target?

In other words, are we asking too much from school buildings? 🧵

@j_g_allen
Classroom
- 500 ft2, 12 kids
- served by a central AC system

To obtain the certificate of occupancy (to be allowed to occupy the classroom), this classroom need to have minimum outside air according to building codes. This is by design and should be kept in operation.
1) The minimum outside air equal to 2.7 ACH.
2) The AC system has a filter - mainly installed to protect the heating and cooling coil - of MERV 8 (pretty common in school buildings). The filter + airflow will get you 2.67 ACH.
Total outside air + MERV 8 filter will get you 5.37 ACH.
Having the minimum outside air (compliant with minimum code) + a basic filter in the AC system will get you to 5+ air exchange rate = in line with Harvard/UC Boulder recommendation.
🚨🚨All what we are asking for is for schools to be compliant to minimum code!

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More from @marwa_zaatari

9 Feb
My school installed an electronic air cleaner system (EAC), what should I do?
1) Ask for the following (part 1):
-Make/model of the system
-What is the basis to choosing the number of units? How many units is needed for the airflow, number of people, ft2?
- How do we verify it is working after it is installed?
Ask for the following (part 2)
- Efficiency test data that correspond to the install (in-room versus duct?)
- By-products test (formaldehyde, ultrafine particles, ozone) test at the SAME conditions of the efficiency test.
Read 16 tweets
8 Feb
Here is a collection of cheating techniques of ionizers when reporting test results 🧵 @jljcolorado
1) Use a small chamber or position their equipment above a tiny surface (example Petri dish) when reporting efficiency to exaggerate the %.
For example, reported efficiency of an equipment positioned above a tiny surface is 93%. Applying to real conditions (duct, with appropriate surface area and contact time), this efficiency will be 0.0016%.
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