1/ Inheritance patterns follow how chromosomes are passed from parents to children. This is a cool concept if your trying to figure out if you got blue eyes from grandma or a dimple in your chin from grandpa, but it becomes very important when studying genetic disorders. 
2/ Each of your parents got 2 chromosomes of each with 23 pairs. One from Grandma and one from Grandpa. They will randomly pass you one of each of those chromosomes.
3/ You could end up with Grandma's Chromosome 1, 2, and 5 while getting Grandpa's chromosome 3, 4 and 6. The process of a chromsosome being deposited into any gamete is 50/50. This is called the law of independent assortment.
4/ The meiosis process ensures each gamete gets 1 of each chromosome, but it selects them randomly. The potential possibilities between the 46 chromosomes of Grandma and the 46 chromosomes Grandpa are over 8 million different chromosome arrangements.
5/ This is to promote variation in our species which helps with evolution and survival. This makes you 50% mom and 50% dad since you get 1 of each chromosome from each of them.
6/ This study of inheritance was developed my Gregor Mendel and is often called Mendellian Genetics instead of Transmission Genetics. It tracks how the possible combinations of genes from the parents get passed to the children.
7/ #Monohybrid_Cross
The monohybrid cross is a tool that allows us to predict the distribution of the gene possibilities.
The monohybrid cross is a tool that allows us to predict the distribution of the gene possibilities.
8/ When we look at a specific gene we will label all of the possible alleles. The picture above shows the use of capital Y for a dominant yellow trait and lower case y for the recessive green trait.
9/ We use this capital letter for dominance and lower case letter for recessive all the time in genetics. Since you can get 1 of 2 possibilities from mom and 1 of 2 possibilities from dad, we use this hybrid cross chart to figure out the possible offspring.
10/ On the right in blue you see the Mom's genes with 1 big Y for Yellow and 1 little y for green. Mom is heterozygous for Yellow and green, but has the phenotype of Yellow as it is a complete dominant gene.
11/ At the top in red, we have dad with 1 big Y for Yellow and 1 little y for green. Dad happens to be heterozygous too.
12/ This is how it works. You match the mom to dad for each box and carry them into that box. In the first box you get the big Y from mom and the big Y from dad. The second box has big Y from mom and little y from dad.
13/ In the 3rd box you have little y from mom and big Y from dad. In the last box you have both little y's in this box from mom and dad. This cross shows you the 4 genotypes.
14/ You will get one homozygous dominant Yellow, 2 Heterozygous Yellow, and 1 homozygous recessive green. Notice the 1:2:1 pattern. This is what happens when you crossbreed 2 heterozygous people.
15/ If you did this cross with mom being homozygous YY yellow, then every single child will be Yellow with their phenotype as yellow is dominant. Below is a hybrid cross diagram of a TT for tall homozygous parent with a homozygous tt recessive parent.
16/ Notice every child ends up with a heterozygous genotype, but will all end up with a tall phenotype as it is the dominant trait. You can do these hybrid crosses for any gene. You just put one parent on the left and the other across the top and match them up.
17/ Once you are use to these ratios of the genotypes, you can translate this into probability ratios.
18/ When you see a parent with TtYy and another parent with TtYy, you can quickly do the math for these children using math. Each probability is 1 in 4 for the monohybrid and using 2 traits gets you to 1 in 16 for each possibility as it becomes ¼ * ¼.
19/ There is a 1/16th chance for a TTYY child and a 1/16th chance for a ttyy child. Getting into the math of probability is way to complex for this genetics guide, but you can find many Youtube videos on the use of probability calculation in genetics.
20/ Then you can calculate a problem like parent 1 has AaBbCcDdEe genotype and breeds with parent 2 having a AaBbCcDdEe phenotype, what is the odds of getting a child with aabbccddee genotype?
21/ You can do the probability of each child to find out what are the odds of getting the child that had all 5 recessive alleles of aabbccddee. The math is ¼ * ¼ * ¼ * ¼ * ¼ = 1 in 1024.
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