, 4 tweets, 1 min read
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When judging the hackathon today I discovered a cool fact: if you normalize each judge's set of scores for different projects to (mean 0, standard deviation 1) and take the project with the highest average normalized score at the winner, that's equivalent to quadratic voting.
Proof: forcing standev=1 means forcing variance=1, and if mean=0 then that means the sum of squares equals 1, which is the quadratic voting budget rule.
Sorry, meant to say the sum of squares equals N, not 1. Doesn't change the conclusion or the reasoning though.
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