Okay, after counts and recounts, we can find NO MOVIE with more than Four INDIVIDUAL Columbo murderers in it.
So which is the most Columbo murdery movie?
Well there are TWO that have four. And breaking that tie is possible, but controversial. Here's why @columbophile /1
So which is the most Columbo murdery movie?
Well there are TWO that have four. And breaking that tie is possible, but controversial. Here's why @columbophile /1
The films:
- Voyage of the Damned (Dunaway, Grant, Werner, Ferrer)
- Greatest Story Ever Told (Pleasance, McDowell, Landau, Ferrer)
Now the obvious way to separate this is to use a McGoohan Value (MGV : number of episodes they played a murderer)
But this is problematic /2
- Voyage of the Damned (Dunaway, Grant, Werner, Ferrer)
- Greatest Story Ever Told (Pleasance, McDowell, Landau, Ferrer)
Now the obvious way to separate this is to use a McGoohan Value (MGV : number of episodes they played a murderer)
But this is problematic /2
Why, because Landau played a set of MURDEROUS IDENTICAL TWINS IN THE SAME EPISODE.
So how does that affect his McGoohan? Is it 1 or 2? He's only in one episode, but he plays TWO murderers within it? /3
So how does that affect his McGoohan? Is it 1 or 2? He's only in one episode, but he plays TWO murderers within it? /3
My current thinking is we should be generous, and declare this a McGoohan of 2 for Landau. In which case Greatest Story Ever Told becomes the most Columbo murdery movie.
BUT, if we can find a film with FIVE murderers we can avoid this fudge... c'mon Twitter, halp! /end
BUT, if we can find a film with FIVE murderers we can avoid this fudge... c'mon Twitter, halp! /end
