Discover and read the best of Twitter Threads about #geometry

Most recents (11)

Hence the absolute need to get out of this voluntary submission system established for at least 300 years.
If you have any suggestions, put them below.
Be creative & let's brainstorm together to perhaps allow us to break these chains of oppression.

#AilanthusAltissima (Mill.) Swingle, 1916
False Japanese varnish, Ailante, Ailanth
« Dwarf Ailanthus is also sometimes nicknamed "the tree of hell" because of its invasive nature and the difficulty of eradicating it. » ImageImage
Read 5 tweets
#geometry #programming
New #geogram tutorial on surface reconstruction from #pointsets:…
Coming next:
- remeshing
- parameterization and texture mapping
Remeshing tutorial rdy !… Image
Read 8 tweets
What do we get if we take the unit circle x² + y² = 1 and complexify it? We get the 3D object (manifold) in 4D space given by the equation
z² + w² = 1
where z, w are complex numbers. Here's one way to see its #geometry. (A slowmo animation to follow.) #calculus
Here is a slow animation of how circles of various radii (centered at the origin) are transformed by the complexified circle function. #math #geometry #calculus
N.B., the reason we see two disconnected loops for the image of circles of small radii is one loop corresponds to the + and other to the - choices in the function u(r,θ). (And, yes, the function w is analytic.)
Read 3 tweets
1/3 | Catriona (@Cshearer41) de 🇬🇧 UK, siempre reta a sus seguidores a resolver problemas de #Geometría.

Me topé con uno interesante(por su rareza) que fue resuelto de varias formas, y aquí le propongo otras dos soluciones

#Geometry #Mathematics
2/3 | Traza BH y FI perpendiculares a BF, luego CM tal que <CMF=BHI, luego se descubren los triángulos congruentes, y la región pedida se convierte en una región trapecial

#Geometry #Mathematics #Geometria
3/3 Traza FH=6 perpendicular a BF, luego los triángulos BFC y JFG son congruentes y GJ resulta paralelo e igual a AB, y los triángulos ABH y GJH son congruentes, y la región pedida se convierte en una región triangular

#Geometry #Mathematics #Geometria
@threadreaderapp unroll
Read 3 tweets
Daily Bookmarks to GAVNet 12/01/2020…
A New AI Study May Explain Why Deep Learning Works | Psychology Today…

#learning #deep #psychology
Geometry Reveals How the World Is Made of Cubes…

#geometry #world
Read 8 tweets
Daily Bookmarks to GAVNet 07/27/2020
CT scans might offer a more accurate way to diagnose Covid-19 - STAT…

#COVID19 #coronavirus #scans #testing
Read 6 tweets
Daily Bookmarks to GAVNet 7/02/2020-2…

Nathaniel Cline and Nathan Tankus: Fiscal Systems, Organizational Capacity, and Crisis: A Political Balance of Payments Approach…

#crisis #payments #balance #systems #capitalism #capacity
We might finally know why the coronavirus spread is out of control again…

#coronavirus #spread
Did protests drive more Covid-19 cases? New research reveals a surprising answer…

#COVID19Cases #research #protests
Read 8 tweets
Daily Bookmarks to GAVNet 6/27/2020-2…

New Geometric Perspective Cracks Old Problem About Rectangles…

#geometry #perspective
Detecting Regions At Risk for Spreading COVID-19 Using Existing Cellular Wireless Network Functionalities - IEEE Journals & Magazine…

#detection #network #coronavirus #regions #wireless #cellular
The Dudes Who Won't Wear Masks - The Atlantic…

#coronavirus #masks
Read 4 tweets
Thread by @isabelrodbar: Are SARS-CoV-2 seroprevalence estimates biased?…

The Great Stagnation—or Decline and Fall? - Intercollegiate Studies Institute: Think. Live Free.…

#civilization #fall #decline
Read 12 tweets
For any subset A of a topological space X, there are no more than 14 sets that can be formed from A using the closure and complement operations. The complement of B is B' = X-B. Closure C(B) = smallest closed set containing B. (Neat problem from Kelley's General #Topology.) #math
There's a lemma that helps one show this. Letting C(A) denote the closure of A, and N(A) the complement of A, we can prove:

Lemma: for all sets A, one has the equation
The result follows from the semigroup with identity I generated by 2 elements N and C such that N² = I, C² = C, and CNCNCNC = CNC. Its 14 elements are:

Should have nice matrix representation. #math
Read 4 tweets

Related hashtags

Did Thread Reader help you today?

Support us! We are indie developers!

This site is made by just two indie developers on a laptop doing marketing, support and development! Read more about the story.

Become a Premium Member ($3.00/month or $30.00/year) and get exclusive features!

Become Premium

Too expensive? Make a small donation by buying us coffee ($5) or help with server cost ($10)

Donate via Paypal Become our Patreon

Thank you for your support!