max(||μ||₂, ||Σ-I||_F)
So if we know that Σ=I (the unknown p is spherical with unit variance), then TV distance between p and N(0,I) is equivalent to ||μ||₂. 2/8
(Up to constants, and thinking of ε as small) 4/8
(Up to constants, and thinking of ε as small) 5/8
(Up to constants, and thinking of ε as small) 6/8
(Up to constants, and thinking of ε as small) 7/8
tl;dr: what is normal may surprise you. 8/8