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For all factual propositions, p, q, and x:
Pr( p -> q | x) = Pr (q | p & x) only if x satisfies the following condition: screening off - Pr (q | x & p) = Pr (q | p)
[The p's and q's are not capital letters now. Deal with it.]
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tandfonline.com/doi/full/10.10…
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cambridge.org/us/academic/su…
- simplicity
- exactness
- similarity
- fruitfulness
Catarina begins by discussing whether the exactness desiderata compels us to scientism? #RFMP2019
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liamkofibright.com/uploads/4/8/9/…
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