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Eric Lombrozo @eric_lombrozo
, 13 tweets, 2 min read Read on Twitter
Happy Holidays. Merry Christmas. Happy Hannukah.

I am in a giving spirit, so I will give 100 mBTC each to ten random people who retweet this on December 25th.
To make this provably fair, let h be the block height of the first block with a timestamp on or after Dec. 25th. I will XOR the hashes of the blocks at heights h and h+5.
Let c be the integer value of the last two bytes, interpret it as a big endian integer (which will range between 0 and 65535).
If it is 0, or the number of RTs is not relatively prime to c, take the previous two bytes. Keep doing this until c is nonzero and relatively prime to the number of RTs. I will only consider RTs made prior to Dec. 25 UTC.
Counting the RTs in order, starting with the first, count off c. That person gets paid. Then count again. If the final RT is reached, we cycle back to the beginning. We continue until 10 people have been selected.
In the highly unlikely scenario that we cannot find two bytes that are coprime to the number of RTs, I will XOR h and h+6. If again this happens, I will XOR h and h+7, and so on until we find a coprime.
should read "to ten random people who retweet this prior to midnight December 25th UTC"
I will wait at least six extra blocks after the h+5 or h+6 or h+7 etc...block before making the calculation.
If you quote the tweet rather than retweet, please quote your quote as a comment.
does not seem to easily allow access to a complete list of timestamped retweets, so in order to enter, please quote the tweet in an original tweet and include the hashtag #2017HolidayBitcoinGiveaway

I am extending the deadline for entry to midnight January 1, 2018
I will be using the block with a timestamp in 2018 UTC and the block 10 blocks after that for the randomization.
Idea for using the hashtag comes from @HIGHSC0R3. Thanks!
I will be changing the randomization algorithm to a secure shuffle, details to be announced.
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